Question 337647
Draw a circle of radius √2.


Draw two perpendicular diameters on this circle.


Join the points where the diameters touch the circle.


You will now have a large square of sides 2 (Pythagoras √2, √2, 2 : root 2 squared plus root 2 squared equals 2 squared)


Divide this square into four (half one way and half the other way)


You will now have four equal squares of sides 1 within the circle with each square touching the circle in only one place and no overlap with any of the other squares.


If you follow this and sketch the diagram you should see the answer is four.