Question 337510
The equation is in vertex form, {{{y=a(x-h)^2+k}}} where ({{{h}}},{{{k}}}) is the vertex.
({{{h}}},{{{k}}})=({{{2}}},{{{0}}})
The axis of symmetry is {{{x=2}}}
Pick points on opposite sides of the axis of symmetry and plot them.
{{{y(1)=y(3)=-1}}}
{{{y(0)=y(4)=-4}}}
{{{y(-1)=y(5)=-9}}}
Plot those points, then draw the curve.
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{{{drawing(300,300,-4,6,-10,2,grid(1),circle(2,0,.2),
blue(line(2,-10,2,10)),
circle(1,-1,.2),
circle(3,-1,.2),
circle(0,-4,.2),
circle(4,-4,.2),
circle(-1,-9,.2),
circle(5,-9,.2),
graph(300,300,-4,6,-10,2,-(x-2)^2))}}}