Question 337496
{{{(12w^4-6w^3+w^2)/(3w^2)=(12w^4)/(3w^2)-(6w^3)/(3w^2)+(w^2)/(3w^2)=4w^2-2w+1/3}}}



This means that {{{(12w^4-6w^3+w^2)/(3w^2)=4w^2-2w+1/3}}}



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