Question 337258
You can't solve it because it doesn't have an "=" sign.
You can simplify it though.
Use a common denominator, {{{x(x+1)}}}
{{{7/(x+1)-3x+2/x=(7x)/(x(x+1))-(3x^2(x+1))/(x(x+1))+(2(x+1))/(x(x+1))}}}
{{{7/(x+1)-3x+2/x=(7x-3x^2(x+1)+2(x+1))/(x(x+1))}}}
{{{7/(x+1)-3x+2/x=(7x-3x^3-3x^2+2x+2)/(x(x+1))}}}
{{{7/(x+1)-3x+2/x=(-3x^3-3x^2+9x+2)/(x(x+1))}}}