Question 337264
{{{5x+2>3x+10 }}}
Solve it like any other algebra problem.
Get the {{{x}}} terms  on the left side, everything else on the right.
Subtract {{{3x }}}from both sides.
{{{5x-3x+2 > 3x-3x+10}}}
{{{2x+2>0+10}}}
{{{2x+2>10}}}
Subtract {{{2}}} from both sides.
{{{2x+2-2>10-2}}}
{{{2x+0>8}}}
{{{2x>8}}}
Divide both sides by {{{2}}}
{{{(2x)/2>8/2}}}
{{{(2/2)x>4}}}
{{{(1)x>4}}}
{{{x>4}}}
.
.
.
Finally, verify the solution.
Pick an {{{x}}} so that {{{x>4}}}.
How about {{{x=5}}}
Test the inequality.
{{{5x+2>3x+10 }}}
{{{5(5)+2>3(5)+10}}}
{{{25+2>15+10}}}
{{{27>25}}}
True. 
Also, choose another {{{x}}} that doesn't satisfy the inequality.
Let {{{x=3}}}
{{{5x+2>3x+10}}}
{{{5(3)+2>3(3)+10}}}
{{{15+2>9+10}}}
{{{17>19}}}
False, but that's what you expected.
So you have a good solution. 
{{{highlight(x>4)}}}