Question 38631
The formula for interest compounded q times per year is:
{{{P = A(1+i/q)^nq}}}
Where: P = Present value.
A = The amount invested ($10,000.00)
i = The rate of interest, as a decimal (0.06)
q = The number of compounding periods (4)
n = The number of years invested (5.5)

Substituting the above into the formula:
{{{P = 10000(1+0.06/4)^(5.5*4)}}} 
{{{P = 10000(1.015)^22}}}
{{{P = 13875.66}}}

The final amount is:
$13,875.66