Question 336936
How do you add rational expressions when one of he denominators is a trinomial and one is a binomial.
ex: {{{4/((y^2 - 3y +2)) + 6/((y^2 -1))}}}
Both denominators will factor
{{{4/((y-2)(y-1)) + 6/((y-1)(y+1))}}}
The common denominator; (y-2)(y-1)(y+1), so we have:
{{{(4(y+1) + 6(y-2))/((y-2)(y-1)(y+1))}}}
:
{{{((4y + 4 + 6y -12))/((y-2)(y-1)(y+1))}}} = {{{((10y - 8))/((y-2)(y-1)(y+1))}}}