Question 336981
Ok Whitney, here's how you would do this.
{{{(4/(3-x))+(2x/(x-3))}}} Take a look at the denominator in the first fraction.
{{{3-x)}}} let's factor out a -1 from this like so:{{{-1(-3+x)}}}
Now we can switch the -3 and the x on the insides of the parentheses to get: {{{-1(x-3)}}} and, as you probably know, we really don't need the 1 in front of the parentheses so we just write it as:{{{-(x-3)}}} and now we can put it back in the fraction.
{{{-(4/(x-3))+2x/(x-3)}}} Now we have our common denominator so we can just add the two numerators together to get:
{{{(-4+2x)/(x-3)}}} and this can be written like:
{{{(2x-4)/(x-3)}}} In the numerator, we can factor out a 2 to get:
{{{highlight(2(x-2)/((x-3)))}}}