Question 336717
{{{x^2+y^2-2x+6y+10=0}}}
Complete the square in x and y.
{{{x^2-2x+y^2+6y+10=0}}}
{{{(x^2-2x+1)+(y^2+6y+9)+10=1+9}}}
{{{(x-1)^2+(y+3)^2+10=10}}}
{{{(x-1)^2+(y+3)^2=0}}}
It's a circle centered at (1,-3) with a radius of zero.
In other words, it is the point (1,-3).
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(1,-3,.1),circle(1,-3,.05),graph(300,300,-5,5,-5,5,0))}}}