Question 336554
The height of the can is equal to {{{6R}}}. 
The volume of the can is 
{{{Vc=pi*R^2*H=pi*R^2(6R)=6*pi*R^3}}}
The volume of the three balls is, 
{{{Vb=3*((4*pi)/3)R^3=4*pi*R^3}}}
The difference is then, 
{{{V=6*pi*R^3-4*pi*R^2}}}
{{{highlight(V=2*pi*R^3)}}}
{{{V=2*pi*(3.5)^3}}}
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{{{highlight_green(V=269.4)}}}cc