Question 336618
Part 1


Long way {{{(x^4)/(x^2)=(x*x*x*x)/(x*x)=(cross(x*x)*x*x)/(cross(x*x))=(x*x)/1=x*x=x^2}}}



So {{{(x^4)/(x^2)=x^2}}} where {{{x<>0}}}



The short cut to simplifying the above is to simply subtract exponents: {{{(x^4)/(x^2)=x^(4-2)=x^2}}}



Before you use the shortcut exclusively, simplify a few more problems using the long way so you understand what's going on.



Part 2


I'll leave this part up to you. Just remember to use the identity {{{(x^(y))/(x^(z))=x^(y-z)}}}



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Jim