Question 336629
What have you tried and how far did you get on this problem?
Solve:
{{{x^2-x = 12}}}Subtract 12 from both sides.
{{{x^2-x-12 = 0}}} Factor this trinomial.
{{{(x+3)(x-4) = 0}}} Apply the zero product rule.
{{{x+3 = 0}}} or {{{x-4 = 0}}} therefore..
{{{x = -3}}} or {{{x = 4}}}