Question 336535
Use the chain rule.
Let {{{u=3/x}}}, {{{du/dx=-3/x^2}}},
{{{y=ln(u)}}}
{{{dy/du=1/u}}}
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{{{dy/dx=(dy/du)*(du/dx)}}}
{{{dy/dx=(1/u)*(-3/x^2)}}}
{{{dy/dx=(x/3)*(-3/x^2)}}}
{{{dy/dx=-1/x}}}