Question 336600
1.{{{x+2y=5}}}
2.{{{2x+y=0}}}
From eq. 2,
{{{y=-2x}}}
Substitute into eq. 1,
{{{x+2(-2x)=5}}}
{{{x-4x=5}}}
{{{-3x=5}}}
{{{highlight(x=-5/3)}}}
Then from eq. 2,
{{{y=-2x}}}
{{{y=-2(-5/3)}}}
{{{highlight(y=10/3)}}}