Question 336582
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Integrate from x=-3 to x=-1 the difference function,
{{{d(x)=-4x+3-(x^2+6)}}}
{{{d(x)=-x^2-4x-3x+C}}}
Integrate to get,
{{{INT=-(1/3)x^3-2x^2-3x}}} evaluated between x=-3 and x=-1.
{{{INT=(-(1/3)(-1)^3)-2(-1)^2-3(-1)+C)-((1/3)(-3)^3-2(-3)^2-3(-3)+C)}}}
{{{INT=(-(1/3)-2+3+C)-(-9-18+9+C)}}}
{{{INT=4/3}}}