<PRE><B>Question 38588</B>
{{{ (x^2+2x-15 )/(4x^2) }}} divided by {{{(x^2-25)/(2x-10) }}}


Since this is a division problem, you need to factor everything possible, and invert the second fraction and multiply.  Now it should look like this:
{{{((x+5)*(x-3))/(4x^2) }}} TIMES {{{ (2(x-5))/((x-5)*(x+5) ) }}}


Divide out the factors of (x+5), (x-5),  and 2, and what is left will be 
{{{ ( x-3)/(2x^2) }}}


R^2 at SCC</PRE>