Question 336212
{{{(3/5)y-3(y+1/2)-5=1+(1/2)(3-(2/3)y)}}} Start with the given equation.



{{{(3/5)y-3y-3/2-5=1+3/2-(2/6)y)}}} Distribute.



{{{(3/5)y-3y-3/2-5=1+3/2-(1/3)y)}}} Reduce.



{{{30((3/cross(5))y)-30(3y)-30(3/cross(2))-30(5)=30(1)+30(3/cross(2))-30((1/cross(3))y)}}} Multiply EVERY term by the LCD {{{30}}} to clear any fractions.



{{{18y-90y-45-150=30+45-10y}}} Distribute and multiply.



{{{-72y-195=30+45-10y}}} Combine like terms on the left side.



{{{-72y-195=-10y+75}}} Combine like terms on the right side.



{{{-72y=-10y+75+195}}} Add {{{195}}} to both sides.



{{{-72y+10y=75+195}}} Add {{{10y}}} to both sides.



{{{-62y=75+195}}} Combine like terms on the left side.



{{{-62y=270}}} Combine like terms on the right side.



{{{y=(270)/(-62)}}} Divide both sides by {{{-62}}} to isolate {{{y}}}.



{{{y=-135/31}}} Reduce.



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Answer:


So the solution is {{{y=-135/31}}}



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