Question 336201
In triangle ABC, angle A is three times as large as angle C. The measure of angle B is 15 degrees less than that of angle C. Find the measure of the angles.
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A = 3C
B = C-15
A + B + C = 180
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Substitute for A and for B and solve for C:
3C + C-15 + C = 180
5C = 195
C = 39 degrees
A = 3C = 3*39 = 117 degrees
B = C-15 = 39-15 = 24 degrees
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Cheers,
Stan H.
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A) 117, 24, 39
B) 78, 24, 39
C) 78, 24, 78
D) 117, 24, 78