Question 336202


{{{(x-5)^2=16}}} Start with the given equation.



{{{x-5=""+-sqrt(16)}}} Take the square root of both sides.



{{{x-5=sqrt(16)}}} or {{{x-5=-sqrt(16)}}} Break up the "plus/minus" to form two equations.



{{{x-5=4}}} or {{{x-5=-4}}}  Take the square root of {{{16}}} to get {{{4}}}.



{{{x=5+4}}} or {{{x=5-4}}} Add {{{5}}} to both sides.



{{{x=9}}} or {{{x=1}}} Combine like terms.



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Answer:



So the solutions are {{{x=9}}} or {{{x=1}}}.



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