<PRE><B>Question 336127</B>
Two angles are complimentary
this means: A+B=90
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The sum of the measure of the first anagle and one-fourth the second angle is 66degrees
This means:  A+(1/4)*B=66
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you have two equations in two unknowns.
Solve the A+B=90 for one of the angles (does not matter which, say A)
A=90-B
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Substitute A=90-B into second equation
A+(1/4)*B=66;  (90-B)+(1/4)*B=66
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solve for B 
90-(3/4)*B=66
-(3/4)*B=66-90=-24
B=(-24)*(-4/3)=32
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substitute B=32 into A=90-B=90-32=58
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