<PRE><B>Question 336175</B>
 How many liters of a 30% alcohol solution must be mixed with 80 liters of a 80% solution to get a 50% solution? 
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Equation:
alcohol+alcohol = alcohol
0.30x + 0.80*80 = 0.50(x+80)
Multiply thru by 100 to get:
30x + 80*80 = 50x + 50*80
-20x = -30*80
x = (3/2)80
x = 120 liters (amt of 30% solution needed in the mixture)
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Cheers,
Stan H.</PRE>