Question 550
{{{(2x^3 - 32x)/(x^2 + 8x + 16)}}}
Factor both the numerator and the denominator.
 
{{{(2x(x^2 - 16))/((x + 4)(x + 4))}}}
Then factor the numerator one more time.
 
{{{(2x(x + 4)(x - 4))/((x + 4)(x + 4))}}}
Then cancel one (x + 4) on the bottom with the (x + 4) on the top.
 
{{{(2x(x -4))/(x + 4)}}}
This is your final answer.