Question 335981


{{{x^3+8x^2+6x+48}}} Start with the given expression



{{{(x^3+8x^2)+(6x+48)}}} Group like terms



{{{x^2(x+8)+6(x+8)}}} Factor out the GCF {{{x^2}}} out of the first group. Factor out the GCF {{{6}}} out of the second group



{{{(x^2+6)(x+8)}}} Since we have the common term {{{x+8}}}, we can combine like terms



So {{{x^3+8x^2+6x+48}}} factors to {{{(x^2+6)(x+8)}}}



In other words, {{{x^3+8x^2+6x+48=(x^2+6)(x+8)}}}



Since the order of the factors does not matter, this means that {{{x^3+8x^2+6x+48=(x+8)(x^2+6)}}} as well



So the answer is C



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Jim