Question 335075
In general, {{{x^(a/b) = root(b, x^a) = (root(b, x))^a}}}
So {{{9p^(7/2) = 9root(2, p^7)}}}
This is a square root and we simplify it by factoring out perfect squares if any:
{{{9root(2, p^7)}}}
{{{9root(2, p^2*p^2*p^2*p)}}}
{{{9root(2, p^2)*root(2, p^2)*root(2, p^2)*root(2, p)}}}
{{{9*p*p*p*root(2, p)}}}
{{{9p^3*root(2, p)}}}