Question 335790
AB-Distance from A to B
BC-Distance from B to C
CD-Distance from C to D
AD-Distance from A to D
.
.
{{{AB=10+BC}}}
{{{BC=10+CD}}}
.
.
{{{AD=390}}}
.
.
{{{AD=AB+BC+CD}}}
.
.
Substitute from above,
{{{AD=10+BC+10+CD+CD}}}
Substitute again for {{{BC}}}
{{{AD=10+(10+CD)+10+CD+CD=390}}}
Solve for {{{CD}}}.
{{{3CD+30=390}}}
{{{3CD=360}}}
{{{CD=120}}}
Now work backwards,
{{{BC=10+CD}}
{{{BC=10+120=130}}}
.
.
{{{AB=10+BC}}}
{{{AB=10+130=highlight(140)}}}