Question 335756
The volume of the toolbox is,
{{{V=L*W*H=80}}}
{{{H=2}}}
{{{W=L-3}}}
Substitute into the volume equation,
{{{L*(L-3)*2=80}}}
{{{L(L-3)=40}}}
{{{L^2-3L-40=0}}}
Factor this quadratic equation,
{{{(L-8)(L+5)=0}}}
Only positive solutions for L are appropriate.
{{{L-8=0}}}
{{{highlight(L=8)}}}
Then from above,
{{{W=L-3}}}
{{{W=8-3}}}
{{{highlight(W=5)}}}