Question 335637
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ p\ :\ \text{the food is good}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ q\ :\ \text{I eat too much}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ r\ :\ \text{I will exercise}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \neg{p}\ :\ \text{the food is } not \text{ good}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \neg{q}\ :\ \text{I } won't \text{ eat too much}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ \neg{r}\ :\ \text{I } won't \text{ exercise}]


If <u>the food is not good</u>, then <u>I won't eat too much</u>.


If *[tex \LARGE \neg{p}], then *[tex \LARGE \neg{q}].


*[tex \LARGE \neg{p}\ \rightarrow\ \neg{q}].


Note:  *[tex \LARGE \neg({p}\ \rightarrow\ {q})] is equivalent to *[tex \LARGE \neg{p}\ \large\wedge\LARGE\ \neg{q}]. Not the same thing as *[tex \LARGE \neg{p}\ \rightarrow\ \neg{q}] at all.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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