Question 335573
Find the coordinates of A.
x coordinate: {{{x=x1+(2/3)(x2-x1)=1+(2/3)(-8-1)=1-6=-5}}}
y coordinate: {{{y=y1+(2/3)(y2-y1)=10+(2/3)(4-10)=10-4=6}}}
A:({{{-5}}},{{{6}}})
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Find the midpoint of (0,-7) and (6,-11)
{{{xm=(x1+x2)/2=(0+6)/2}}}
{{{ym=(y1+y2)/2=(-7-11)/2}}}
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Complete the calculation to find the midpoint.
Then use the distance formula to calculate AB.
{{{AB^2=(-5-xm)^2+(6-ym)^2}}}
{{{AB=sqrt((-5-xm)^2+(6-ym)^2)}}}
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{{{drawing(300,300,-10,8,-12,12,
grid(1),
circle(0,-7,.3),
circle(6,-11,.3),
circle(1,10,.3),
circle(-8,4,.3),
circle(-5,6,.4),
circle(3,-9,.4),
locate(3,-10,B),
locate(-5,8,A),
line(0,-7,6,-11),
line(1,10,-8,4),
blue(line(3,-9,-5,6)),
graph(300,300,-10,8,-12,12,0))}}}