Question 335679
{{{D=sqrt(L^2+W^2)}}} Start with the formula for the diagonal of a rectangle.



{{{D=sqrt((69)^2+(28)^2)}}} Plug in {{{L=69}}} and {{{W=28}}}.



{{{D=sqrt(4761+(28)^2)}}} Square {{{69}}} to get {{{4761}}}.



{{{D=sqrt(4761+784)}}} Square {{{28}}} to get {{{784}}}.



{{{D=sqrt(5545)}}} Add {{{4761}}} to {{{784}}} to get {{{5545}}}.



{{{D=74.4647567645259}}} Take the square root of {{{5545}}} to get {{{74.4647567645259}}} (this value is approximate).



{{{D=74.5}}} Round to the nearest tenth.



So a rectangle with a length of {{{69}}} inches and a width of {{{28}}} inches has a diagonal length of about {{{74.5}}} inches.