<PRE><B>Question 38557</B>
the question is write an equation for the perpendicular bisector of the line segment joining the two points?
the pionts are A-(0,0).............AND B-(-8,-10)
how would you solve this
MID POINT OF AB ...SAY....C...IS (0-8)/2,(0-10)/2=(-4,-5)
SLOPE OF AB =(0+10)/(0+8)=10/8=5/4
SLOPE OF PERPENDICULAR TO AB IS -1/(5/4)=-4/5
PERPENDICULAR BISECTOR IS PERPENDICULAR TO AB AND PASSES THROUGH ITS MID POINT C.HENCE ITS EQN. IS 
Y+5=(-4/5)(X+4)
5Y+25=-4X-16
4X+5Y+41=0</PRE>