Question 335400
Use the trig identity,
{{{sin(2x)=2sin(x)cos(x)}}}
.
.
.
{{{sin(2x)=sin(x)}}}
{{{2sin(x)cos(x)=sin(x)}}}
{{{2sin(x)cos(x)-sin(x)=0}}}
{{{sin(x)(2cos(x)-1)=0}}}
Two solutions:
{{{sin(x)=0}}}
Those solutions you already have.
.
.
.
{{{2cos(x)-1=0}}}
{{{2cos(x)=1}}}
{{{cos(x)=1/2}}}
Solve for the remaining two solutions.
.
.
.
{{{drawing(300,300,-1,7,-2,2,
circle(0,0,.2),
circle(pi,0,.2),
circle(2*pi,0,.2),
circle(1.047,0.866,.2),
circle(5.236,-0.866,.2),
graph(300,300,-1,7,-2,2,sin(2x),sin(x)))}}}