Question 335534
Dividing by a fraction is equivalent to multiplying by its reciprocal,
{{{((5x)/(x^2-7x+10))/((4)/(x^2-25)) =((5x)/(x^2-7x+10))*((x^2-25)/(4))}}}
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 {{{((5x)/(x^2-7x+10))/((4)/(x^2-25)) =((5x)/((x-2)(x-5)))*(((x-5)(x+5))/(4))}}}
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 {{{((5x)/(x^2-7x+10))/((4)/(x^2-25)) =((5x)/((x-2)cross((x-5))))*((cross((x-5))(x+5))/(4))}}}
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 {{{((5x)/(x^2-7x+10))/((4)/(x^2-25)) =(5x(x+5))/(4(x-2))}}}
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