Question 335512
The domain of the function is x values for which f(x) exists.
Since the square root requires non-negative arguments.
{{{x-2>=0}}}
{{{x>=2}}}
That's the domain.
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Values for f(x) begin at 0 (at {{{x=2}}}) and get greater with increasing x.
So the range is {{{f(x)>=0}}}