Question 335499
It's all x values for which f(x) is defined.
f(x) is undefined when the denominator equals zero.
Solve {{{x^2+5x+4=0}}}
{{{(x+1)(x+4)=0}}}
Two solutions:{{{x+1=0}}}
{{{x=-1}}}
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{{{x+4=0}}}
{{{x=-4}}}
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The domain is therefore all x values except {{{x=-1}}} and {{{x=-4}}}.