Question 335484
{{{3*abs(2a+5)+2*abs(3-a)}}} Start with the given expression.



{{{3*abs(2(4)+5)+2*abs(3-4)}}} Plug in {{{a=4}}}



{{{3*abs(8+5)+2*abs(3-4)}}} Multiply



{{{3*abs(13)+2*abs(-1)}}} Combine like terms.



{{{3(13)+2(1)}}} Evaluate the absolute values.



{{{39+2}}} Multiply



{{{41}}} Add



So {{{3*abs(2(4)+5)+2*abs(3-4)=41}}}



This means that {{{3*abs(2a+5)+2*abs(3-a)=41}}} when {{{a=4}}}