Question 334258
{{{((5u^2v)/(2uv^2))((-3uv)/(2u^2v))^3=((5u^2v)/(2uv^2))((-27u^3v^3)/(8u^6v^3))}}}
{{{((5u^2v)/(2uv^2))((-3uv)/(2u^2v))^3=(5/2)(-27/8)u^(2-1+3-6)v^(1-2+3-3)}}}
{{{((5u^2v)/(2uv^2))((-3uv)/(2u^2v))^3=-(135/16)u^(-2)v^(-1)}}}
{{{((5u^2v)/(2uv^2))((-3uv)/(2u^2v))^3=-135/(16u^2v)}}}