Question 335261
You don't show any steps of how you got to your answer and it's not a final answer either.
{{{x^2=9}}} cannot be solution since it would lead to a division by zero. 
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Use the common denominator, {{{x^2-9=(x-3)(x+3)}}}
{{{x/(x^2-9) + 4/(x+3) = 3/(x^2-9) }}}
{{{x/(x^2-9) + (4(x-3))/((x+3)(x-3)) = 3/(x^2-9) }}}
{{{(x+4(x-3)-3)/(x^2-9)=0}}}
{{{(x+4x-12-3)/(x^2-9)=0}}}
{{{(5x-15)/(x^2-9)=0}}}
{{{(5(x-3))/((x-3)(x+3))=0}}}
{{{5/(x+3)=0}}}
No solution.