Question 334052
Use the common denominator, {{{(x+3)(x-3)}}}
{{{1/(x+3)+2/(x-3)=(x-3)/((x+3)(x-3))+(2(x+3))/((x+3)(x-3))}}}
{{{1/(x+3)+2/(x-3)=(x-3+2x+6)/((x+3)(x-3))}}}
{{{1/(x+3)+2/(x-3)=(3x+3)/((x+3)(x-3))}}}
{{{1/(x+3)+2/(x-3)=(3(x+1))/((x+3)(x-3))}}}