Question 335151
6x-y=-35-------------(1)

5x-2y=-35-------------(2)

 since both the equations are equal to -35
(1)=(2)

6x-y =5x-2y
6x-5x=y-2y
x=-y
now substitute the value of x in any one of the equation

x=-y
6x-y= -35
6(-y) -y=-35
-7y = -35
y=-35/-7
y=5

put y = 5 in (1)

6x-y =-35
6x-5=-35

6x =-35+5
6x=-30
x= -30/6
x=-5

ie,
x= -5
and  y= 5

Proof:

6x-y=-35
6(-5) -5 =-35
-30-5=-35
-35=-35
or
 5x-2y =-35
5(-5) -2*5 =-35
-25-10 =-35
-35=-35
LHS =RHS