Question 335160
2y^2-2y +37=(y-5)^2
solution:

(y-5)^2 = y^2 -10y+25

2y^2 -2y +37 = y^2 -10y +25
simplify 

2y^2-y^2 -2y +10y +37-25 =0
y^2+8y +12=0
now factor this equation

y^2+8y+12 =0
y^2 +6y+2y+12 =0
y(y+6) +2(y+6) =0
(y+2)(y+6) =0
y+2=0 or y+6 =0
 y=-2 or y=-6

therefore the value of y is

y= -2 or  -6