<PRE><B>Question 335156</B>
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You have correctly solved for the ordered pair that is the solution set to your system of equations.  Now for the graphing:


Start with either one of your equations.


&lt;b&gt;Step 1.&lt;/b&gt;  Pick a value for &lt;i&gt;a&lt;/i&gt;.  It can be anything you like, but 0, 1, or some other small integer usually works well and makes the arithmetic easier.


&lt;b&gt;Step 2.&lt;/b&gt;  Substitute that value in place of &lt;i&gt;a&lt;/i&gt; in your equation.  Do the arithmetic and determine the value of &lt;i&gt;b&lt;/i&gt; that results.


&lt;b&gt;Step 3.&lt;/b&gt;  Take the value of &lt;i&gt;a&lt;/i&gt; that you selected for step 1 and the value of &lt;i&gt;b&lt;/i&gt; that you calculated in step 2 and form an ordered pair (&lt;i&gt;a&lt;/i&gt;,&lt;i&gt;b&lt;/i&gt;).


&lt;b&gt;Step 4.&lt;/b&gt;  Plot the ordered pair from Step 3 on your graph.  Since we chose to make the ordered pair in alphabetical order,  the &lt;i&gt;a&lt;/i&gt; value is the distance right or left along the horizontal axis and the &lt;i&gt;b&lt;/i&gt; value is the distance up or down along the vertical axis.


&lt;b&gt;Step 5.&lt;/b&gt;  Repeat steps 1 through 4 with a different value for &lt;i&gt;a&lt;/i&gt;.


&lt;b&gt;Step 6.&lt;/b&gt;  Draw a line across your graph that passes through the two points that you plotted.


&lt;b&gt;Step 7.&lt;/b&gt;  Repeat steps 1 through 6 using the other equation.


The point where the lines intersect is the solution, because the coordinates of that point will satisfy (read: make true) both of your equations.  You need to determine, by inspection of the graph, what the coordinates of that point are and report your answer as an ordered pair, (&lt;i&gt;a&lt;/i&gt;,&lt;i&gt;b&lt;/i&gt;), using those coordinates.  To check your answer, you should substitute this set of coordinates into each of your original equations and verify that you have a true statement for each of the equations.


The point where a line crosses the horizontal axis is the &lt;i&gt;a&lt;/i&gt; intercept, and the ordered pair is of the form (&lt;i&gt;*[tex \Large \alpha]&lt;/i&gt;,&lt;i&gt;0&lt;/i&gt;).  The &lt;i&gt;b&lt;/i&gt; intercept, (&lt;i&gt;0&lt;/i&gt;,&lt;i&gt;*[tex \Large \beta]&lt;/i&gt;), is where the line crosses the vertical axis. 


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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