Question 335028
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Let *[tex \Large x] represent the measure of the length of one side of the square and the measure of the shortest side of the triangle.  The other two sides of the triangle, being consecutive even integers, are *[tex \Large x\ +\ 2] and *[tex \Large x +\ 4].


The perimeter of the square is *[tex \Large 4x].  The perimeter of the triangle is *[tex \Large x \ +\ x\ +\ 2\ +\ x\ +\ 4\ =\ 3x\ +\ 6].  And the two perimeters are equal, so:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 4x\ =\ 3x\ +\ 6]


Solve for *[tex \Large x] to get the measure of a side of the square, and multiply that by 4 to get the perimeter.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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