Question 38519
Perimeter = 2l + 2w
Where the length = (w-5)
Where the width = (w)
56 = 2(w-5) + 2(w)
56 = 2w - 10 + 2w
66 = 4w
16.5 = w
11.5 = l
Doesn't the length's measure generally is greater than the width?