Question 38471
Area of triangle = {{{.5st}}} where 's' is the base and 't' is the height
{{{2c^2-8=(.5)(c+2)(t)}}}
{{{(2c^2-8)/(c+2)=(.5)t}}}
{{{(2(c^2-4))/(c+2)=(.5)t}}}
{{{(2(c+2)(c-2))/(c+2)=(.5)t}}}
{{{(2(c-2))=(.5)t}}}
{{{(2(c-2))/.5=t}}}
{{{(4(c-2))=t}}}
{{{(4c-8))=t}}}