Question 334995
16x^2-8x+1=0 
(4x-1)(4x-1)=0
4x-1=0
4x=1
x-1/4 ans.
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2x^2=4x+1
2x^2-4x-1)=0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}} 
x=(4+-sqrt[-4^2-4*2*-1])/2*2
x=(4+-sqrt[16+8])/4
x=(4+-sqrt24)/4
x=(4+-4.9)/4
x=4+4.9)/4
x=8.9/4
x=2.25 ans.
x=(4-4.9)/4
x=-.9/4
x=.225 ans.