Question 334974
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Your first step was correct.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ N\ =\ \frac{-8.4\ -\ 0.63B}{0.37}]


Now take the right hand side mess and replace N in the second equation.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.56B\ +\ 0.44\left(\frac{-8.4\ -\ 0.63B}{0.37}\right)\ =\ -6.4]


Now you have an equation, albeit an extremely ugly one, in one variable that can be solved by ordinary algebraic means.  Once you have a value for *[tex \Large B], you can substitute that value back into either of the original equations to produce a single-variable equation in *[tex \Large N].


This is mostly just nasty arithmetic.  Enjoy.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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