Question 334978
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Remember the distributive property?


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ a(b\ +\ c) =\ ab\ +\ ac?]


Use it in reverse to factor out your *[tex \Large v]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 5rv\ -\ sv\ =\ 2r]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ v(5r\ -\ s)\ =\ 2r]


Now multiply by *[tex \Large \frac{1}{5r\,-\,s}]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ v\ =\ \frac{2r}{5r\,-\,s}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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