Question 334973
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ P\left(1\ +\ \frac{r}{n}\right)^{nt}]


For your problem, *[tex \Large P\ =\ 150], *[tex \Large r\ =\ 0.06] (for 6%), *[tex \Large n\ =\ 2] (for semiannually), and *[tex \Large t\ =\ 10] years]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ A\ =\ 150\left(1\ +\ \frac{0.06}{2}\right)^{2(10)}]


I'll leave you alone to spend some nice quality time with your calculator.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
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