Question 334950
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Use the two-point form of an equation of a line to write an equation of the line containing the given segment.


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


So:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ =\ \frac{2}{3}x]


Drop a vertical from the point *[tex \Large (9,6)] to the *[tex \Large x] axis at the point *[tex \Large (9,0)]


Now you have a triangle.  If you divide the segment from *[tex \Large (0,0)] to *[tex \Large (9,0)] into three equal segments by marking points at *[tex \Large (3,0)] and *[tex \Large (6,0)].  Use these *[tex \Large x] coordinates in the equation developed above to find the *[tex \Large y] coordinates of the points on the given segment that divide the segment into three parts.  The principle is similar triangles.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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