Question 334901
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The lateral surface area of a cone, *[tex \Large S] is given by:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ S\ =\ \pi{rs}]


Where *[tex \Large r] is the radius of the base and *[tex \Large s] is the slant height.


Knowing *[tex \Large r] (one-half of the diameter), and the height, *[tex \Large  h], use Pythagoras to calculate the slant height:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ s\ =\ \sqrt{r^2\ +\ h^2}]


Putting it all together in one formula:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ S\ =\ \pi{r\sqrt{r^2\ +\ h^2}}]


Just plug in your values and do the arithmetic.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
My calculator said it, I believe it, that settles it
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